3.2772 \(\int \frac {(c x)^{4+n}}{a+b x^n} \, dx\)

Optimal. Leaf size=44 \[ \frac {(c x)^{n+5} \, _2F_1\left (1,\frac {n+5}{n};2+\frac {5}{n};-\frac {b x^n}{a}\right )}{a c (n+5)} \]

[Out]

(c*x)^(5+n)*hypergeom([1, (5+n)/n],[2+5/n],-b*x^n/a)/a/c/(5+n)

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Rubi [A]  time = 0.02, antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 1, number of rules used = 1, integrand size = 17, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.059, Rules used = {364} \[ \frac {(c x)^{n+5} \, _2F_1\left (1,\frac {n+5}{n};2+\frac {5}{n};-\frac {b x^n}{a}\right )}{a c (n+5)} \]

Antiderivative was successfully verified.

[In]

Int[(c*x)^(4 + n)/(a + b*x^n),x]

[Out]

((c*x)^(5 + n)*Hypergeometric2F1[1, (5 + n)/n, 2 + 5/n, -((b*x^n)/a)])/(a*c*(5 + n))

Rule 364

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a^p*(c*x)^(m + 1)*Hypergeometric2F1[-
p, (m + 1)/n, (m + 1)/n + 1, -((b*x^n)/a)])/(c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rubi steps

\begin {align*} \int \frac {(c x)^{4+n}}{a+b x^n} \, dx &=\frac {(c x)^{5+n} \, _2F_1\left (1,\frac {5+n}{n};2+\frac {5}{n};-\frac {b x^n}{a}\right )}{a c (5+n)}\\ \end {align*}

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Mathematica [A]  time = 0.01, size = 44, normalized size = 1.00 \[ \frac {x (c x)^{n+4} \, _2F_1\left (1,\frac {n+5}{n};\frac {n+5}{n}+1;-\frac {b x^n}{a}\right )}{a (n+5)} \]

Antiderivative was successfully verified.

[In]

Integrate[(c*x)^(4 + n)/(a + b*x^n),x]

[Out]

(x*(c*x)^(4 + n)*Hypergeometric2F1[1, (5 + n)/n, 1 + (5 + n)/n, -((b*x^n)/a)])/(a*(5 + n))

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fricas [F]  time = 0.66, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\left (c x\right )^{n + 4}}{b x^{n} + a}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^(4+n)/(a+b*x^n),x, algorithm="fricas")

[Out]

integral((c*x)^(n + 4)/(b*x^n + a), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\left (c x\right )^{n + 4}}{b x^{n} + a}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^(4+n)/(a+b*x^n),x, algorithm="giac")

[Out]

integrate((c*x)^(n + 4)/(b*x^n + a), x)

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maple [F]  time = 0.22, size = 0, normalized size = 0.00 \[ \int \frac {\left (c x \right )^{n +4}}{b \,x^{n}+a}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^(n+4)/(b*x^n+a),x)

[Out]

int((c*x)^(n+4)/(b*x^n+a),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \frac {c^{n + 4} x^{5}}{5 \, b} - a c^{n + 4} \int \frac {x^{4}}{b^{2} x^{n} + a b}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)^(4+n)/(a+b*x^n),x, algorithm="maxima")

[Out]

1/5*c^(n + 4)*x^5/b - a*c^(n + 4)*integrate(x^4/(b^2*x^n + a*b), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.02 \[ \int \frac {{\left (c\,x\right )}^{n+4}}{a+b\,x^n} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((c*x)^(n + 4)/(a + b*x^n),x)

[Out]

int((c*x)^(n + 4)/(a + b*x^n), x)

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sympy [C]  time = 8.24, size = 97, normalized size = 2.20 \[ \frac {c^{4} c^{n} x^{5} x^{n} \Phi \left (\frac {b x^{n} e^{i \pi }}{a}, 1, 1 + \frac {5}{n}\right ) \Gamma \left (1 + \frac {5}{n}\right )}{a n \Gamma \left (2 + \frac {5}{n}\right )} + \frac {5 c^{4} c^{n} x^{5} x^{n} \Phi \left (\frac {b x^{n} e^{i \pi }}{a}, 1, 1 + \frac {5}{n}\right ) \Gamma \left (1 + \frac {5}{n}\right )}{a n^{2} \Gamma \left (2 + \frac {5}{n}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((c*x)**(4+n)/(a+b*x**n),x)

[Out]

c**4*c**n*x**5*x**n*lerchphi(b*x**n*exp_polar(I*pi)/a, 1, 1 + 5/n)*gamma(1 + 5/n)/(a*n*gamma(2 + 5/n)) + 5*c**
4*c**n*x**5*x**n*lerchphi(b*x**n*exp_polar(I*pi)/a, 1, 1 + 5/n)*gamma(1 + 5/n)/(a*n**2*gamma(2 + 5/n))

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